Question

using the sides, find the two points forming the hypotenuse. (1, 9) and (4, 6) click twice to draw a line. click a segment to erase it. attempt 1 out of 2 leg 2: hypotenuse:

Explanation:

Step1: Find the length of leg 1 (change in x - direction)

Let $(x_1,y_1)=(1,9)$ and $(x_2,y_2)=(4,6)$. The length of leg 1 (horizontal side) is $|x_2 - x_1|=|4 - 1| = 3$.

Step2: Find the length of leg 2 (change in y - direction)

The length of leg 2 (vertical side) is $|y_2 - y_1|=|6 - 9|=3$.

Step3: Use the Pythagorean theorem to find the hypotenuse

The Pythagorean theorem is $c=\sqrt{a^{2}+b^{2}}$, where $a = 3$ and $b = 3$. So $c=\sqrt{3^{2}+3^{2}}=\sqrt{9 + 9}=\sqrt{18}=3\sqrt{2}$.

Answer:

Leg 1: 3
Leg 2: 3
Hypotenuse: $3\sqrt{2}$