Question

valor: 100 puntos
instrucciones: realizar los cálculos completos
fecha de entrega: 3 de octubre de 2025

1. adam se nadó. en una competencia nadó una distancia de 3000 m en 85 minutos. calcula la velocidad.
2. yaniela figueroa corrió una distancia de 5000 metros en 90 segundos.

calcula la velocidad.

1. edno es un corredor. durante un evento recorrió 8000 metros en 5 minutos. calcula la velocidad y expresa el resultado en km/h.
2. malachi, niive mercado se juega en el hipódromo de puerto rico.

en una carrera se desplazó con su caballo 10,000 metros en 9 segundos.
calcula la velocidad.

1. alexis rivera en un ataque de 95 segundos. en una carrera se

desplazó 7,000 metros en 95 segundos. calcula la velocidad y
expresa el resultado en km/h.

1. kahliah corrió 8000 metros en 15 segundos. calcula la velocidad.
2. un caballo en una carrera recorrió 12,000 m en 15 minutos. calcula la

velocidad.

1. un avión despega del aeropuerto. recorre una distancia de

1,000,000 de metros en 12 horas. calcula la velocidad y expresa el
resultado en km/h.

1. un perro de raza husky corre una distancia de 85 m en 5 segundos.

calcula la velocidad y expresa el resultado en km/h.

1. un ciclista recorrió una distancia de 600 m en 20 minutos.

fórmula: v = d/t
maestro: alexis rivera esquilin

Explanation:

Step1: Recall velocity formula

The formula for velocity is $v = \frac{d}{t}$, where $v$ is velocity, $d$ is distance and $t$ is time. We need to make sure the units are consistent for calculations and convert as necessary for the final - required units.

Step2: Solve problem 1

Adam walked a distance $d_1 = 3000$ m in $t_1=85$ s. First, calculate the velocity in m/s: $v_1=\frac{d_1}{t_1}=\frac{3000}{85}\approx35.29$ m/s. To convert to km/h, use the conversion factors: $1$ km = $1000$ m and $1$ h = $3600$ s. So $v_1 = 35.29\times\frac{3600}{1000}=35.29\times3.6\approx127.04$ km/h.

Step3: Solve problem 2

Yasmin Figueroa ran a distance $d_2 = 5000$ m in $t_2 = 90$ s. The velocity in m/s is $v_2=\frac{d_2}{t_2}=\frac{5000}{90}\approx55.56$ m/s. Converting to km/h: $v_2=55.56\times\frac{3600}{1000}=55.56\times3.6\approx200$ km/h.

Step4: Solve problem 3

Edro ran a distance $d_3 = 8000$ m in $t_3 = 5$ minutes. Since $5$ minutes = $5\times60 = 300$ s, the velocity in m/s is $v_3=\frac{d_3}{t_3}=\frac{8000}{300}\approx26.67$ m/s. Converting to km/h: $v_3=26.67\times\frac{3600}{1000}=26.67\times3.6\approx96$ km/h.

Step5: Solve problem 4

Ninive Mercedes and her horse ran a distance $d_4 = 10000$ m in $t_4 = 9$ seconds. The velocity in m/s is $v_4=\frac{d_4}{t_4}=\frac{10000}{9}\approx1111.11$ m/s. Converting to km/h: $v_4=1111.11\times\frac{3600}{1000}=1111.11\times3.6\approx4000$ km/h.

Step6: Solve problem 5

Alexis Rivera ran a distance $d_5 = 7000$ m in $t_5 = 95.5$ seconds. The velocity in m/s is $v_5=\frac{d_5}{t_5}=\frac{7000}{95.5}\approx73.3$ m/s. Converting to km/h: $v_5=73.3\times\frac{3600}{1000}=73.3\times3.6\approx264$ km/h.

Step7: Solve problem 6

Kahlil ran a distance $d_6 = 8000$ m in $t_6 = 15$ seconds. The velocity in m/s is $v_6=\frac{d_6}{t_6}=\frac{8000}{15}\approx533.33$ m/s. Converting to km/h: $v_6=533.33\times\frac{3600}{1000}=533.33\times3.6\approx1920$ km/h.

Step8: Solve problem 7

A horse ran a distance $d_7 = 12000$ m in $t_7 = 15$ minutes. Since $15$ minutes = $15\times60 = 900$ s, the velocity in m/s is $v_7=\frac{d_7}{t_7}=\frac{12000}{900}\approx13.33$ m/s. Converting to km/h: $v_7=13.33\times\frac{3600}{1000}=13.33\times3.6\approx48$ km/h.

Step9: Solve problem 8

A bird flew a distance $d_8 = 1000$ m in $t_8 = 12$ hours. First, convert hours to seconds: $t_8 = 12\times3600 = 43200$ s. The velocity in m/s is $v_8=\frac{d_8}{t_8}=\frac{1000}{43200}\approx0.023$ m/s. Converting to km/h: $v_8=0.023\times\frac{3600}{1000}=0.023\times3.6\approx0.083$ km/h.

Step10: Solve problem 9

A person ran a distance $d_9 = 85$ m in $t_9 = 5$ seconds. The velocity in m/s is $v_9=\frac{d_9}{t_9}=\frac{85}{5}=17$ m/s. Converting to km/h: $v_9=17\times\frac{3600}{1000}=17\times3.6 = 61.2$ km/h.

Step11: Solve problem 10

A person walked a distance $d_{10}=600$ m in $t_{10}=20$ minutes. Since $20$ minutes = $20\times60 = 1200$ s, the velocity in m/s is $v_{10}=\frac{d_{10}}{t_{10}}=\frac{600}{1200}=0.5$ m/s. Converting to km/h: $v_{10}=0.5\times\frac{3600}{1000}=0.5\times3.6 = 1.8$ km/h.

Since you didn't ask for a specific problem's answer, here are all the velocities calculated above for each of the 10 problems. If you want a specific one, please specify.

Answer:

Step1: Recall velocity formula

The formula for velocity is $v = \frac{d}{t}$, where $v$ is velocity, $d$ is distance and $t$ is time. We need to make sure the units are consistent for calculations and convert as necessary for the final - required units.

Step2: Solve problem 1

Adam walked a distance $d_1 = 3000$ m in $t_1=85$ s. First, calculate the velocity in m/s: $v_1=\frac{d_1}{t_1}=\frac{3000}{85}\approx35.29$ m/s. To convert to km/h, use the conversion factors: $1$ km = $1000$ m and $1$ h = $3600$ s. So $v_1 = 35.29\times\frac{3600}{1000}=35.29\times3.6\approx127.04$ km/h.

Step3: Solve problem 2

Yasmin Figueroa ran a distance $d_2 = 5000$ m in $t_2 = 90$ s. The velocity in m/s is $v_2=\frac{d_2}{t_2}=\frac{5000}{90}\approx55.56$ m/s. Converting to km/h: $v_2=55.56\times\frac{3600}{1000}=55.56\times3.6\approx200$ km/h.

Step4: Solve problem 3

Edro ran a distance $d_3 = 8000$ m in $t_3 = 5$ minutes. Since $5$ minutes = $5\times60 = 300$ s, the velocity in m/s is $v_3=\frac{d_3}{t_3}=\frac{8000}{300}\approx26.67$ m/s. Converting to km/h: $v_3=26.67\times\frac{3600}{1000}=26.67\times3.6\approx96$ km/h.

Step5: Solve problem 4

Ninive Mercedes and her horse ran a distance $d_4 = 10000$ m in $t_4 = 9$ seconds. The velocity in m/s is $v_4=\frac{d_4}{t_4}=\frac{10000}{9}\approx1111.11$ m/s. Converting to km/h: $v_4=1111.11\times\frac{3600}{1000}=1111.11\times3.6\approx4000$ km/h.

Step6: Solve problem 5

Alexis Rivera ran a distance $d_5 = 7000$ m in $t_5 = 95.5$ seconds. The velocity in m/s is $v_5=\frac{d_5}{t_5}=\frac{7000}{95.5}\approx73.3$ m/s. Converting to km/h: $v_5=73.3\times\frac{3600}{1000}=73.3\times3.6\approx264$ km/h.

Step7: Solve problem 6

Kahlil ran a distance $d_6 = 8000$ m in $t_6 = 15$ seconds. The velocity in m/s is $v_6=\frac{d_6}{t_6}=\frac{8000}{15}\approx533.33$ m/s. Converting to km/h: $v_6=533.33\times\frac{3600}{1000}=533.33\times3.6\approx1920$ km/h.

Step8: Solve problem 7

A horse ran a distance $d_7 = 12000$ m in $t_7 = 15$ minutes. Since $15$ minutes = $15\times60 = 900$ s, the velocity in m/s is $v_7=\frac{d_7}{t_7}=\frac{12000}{900}\approx13.33$ m/s. Converting to km/h: $v_7=13.33\times\frac{3600}{1000}=13.33\times3.6\approx48$ km/h.

Step9: Solve problem 8

A bird flew a distance $d_8 = 1000$ m in $t_8 = 12$ hours. First, convert hours to seconds: $t_8 = 12\times3600 = 43200$ s. The velocity in m/s is $v_8=\frac{d_8}{t_8}=\frac{1000}{43200}\approx0.023$ m/s. Converting to km/h: $v_8=0.023\times\frac{3600}{1000}=0.023\times3.6\approx0.083$ km/h.

Step10: Solve problem 9

A person ran a distance $d_9 = 85$ m in $t_9 = 5$ seconds. The velocity in m/s is $v_9=\frac{d_9}{t_9}=\frac{85}{5}=17$ m/s. Converting to km/h: $v_9=17\times\frac{3600}{1000}=17\times3.6 = 61.2$ km/h.

Step11: Solve problem 10

A person walked a distance $d_{10}=600$ m in $t_{10}=20$ minutes. Since $20$ minutes = $20\times60 = 1200$ s, the velocity in m/s is $v_{10}=\frac{d_{10}}{t_{10}}=\frac{600}{1200}=0.5$ m/s. Converting to km/h: $v_{10}=0.5\times\frac{3600}{1000}=0.5\times3.6 = 1.8$ km/h.

Since you didn't ask for a specific problem's answer, here are all the velocities calculated above for each of the 10 problems. If you want a specific one, please specify.