Question

value: 4
which of the following formulas has one carbon atom and four hydrogen atoms?
a. $\ce{c6h12o6}$ (sugar)
b. $\ce{c2h6o}$ (alcohol)
c. $\ce{c4h10}$ (butane)
d. $\ce{ch4}$ (methane)

Explanation:

To determine which formula has 1 Carbon (C) atom and 4 Hydrogen (H) atoms, we analyze each option:

• Option a: $\ce{C6H12O6}$ has 6 C and 12 H atoms.
• Option b: $\ce{C2H6O}$ has 2 C and 6 H atoms.
• Option c: $\ce{C4H10}$ has 4 C and 10 H atoms.
• Option d: $\ce{CH4}$ has 1 C (implied by the single C without a subscript) and 4 H atoms (from the subscript 4 on H).

Answer:

d. $\ce{CH4}$ (Methane)