Question

the vapor pressure of solid iodine at 25 °c is 0.00186 atm. calculate the vapor pressure in mmhg and torr. round each of your answers to 3 significant digits.

Explanation:

Step1: Recall pressure conversion factor

We know that \( 1\ \text{atm} = 760\ \text{mmHg} = 760\ \text{torr} \).

Step2: Convert pressure to mmHg

Given pressure \( P = 0.00186\ \text{atm} \). To convert to mmHg, use the conversion factor:
\( P_{\text{mmHg}} = 0.00186\ \text{atm} \times \frac{760\ \text{mmHg}}{1\ \text{atm}} \)
\( P_{\text{mmHg}} = 0.00186\times760 = 1.4136\ \text{mmHg} \approx 1.41\ \text{mmHg} \) (rounded to 3 significant digits)

Step3: Convert pressure to torr

Since \( 1\ \text{mmHg} = 1\ \text{torr} \), the pressure in torr will be the same as in mmHg (because the conversion factor between mmHg and torr is 1:1). So,
\( P_{\text{torr}} = 0.00186\ \text{atm} \times \frac{760\ \text{torr}}{1\ \text{atm}} \)
\( P_{\text{torr}} = 0.00186\times760 = 1.4136\ \text{torr} \approx 1.41\ \text{torr} \) (rounded to 3 significant digits)

Answer:

Vapor pressure in mmHg: \( \boldsymbol{1.41\ \text{mmHg}} \)
Vapor pressure in torr: \( \boldsymbol{1.41\ \text{torr}} \)