Question

the venn diagram below shows the data collected at a sandwich shop for the last six months with respect to the type of bread people ordered (sourdough or wheat) and whether or not they got cheese on their sandwich. use this data to answer the following question: what is the probability that a randomly - selected person would choose sourdough or without cheese? p(sourdough ∪ no cheese)=p(sourdough or no cheese)=

Explanation:

Step1: Recall probability - union formula

$P(A\cup B)=P(A)+P(B)-P(A\cap B)$
Let $A$ be the event of choosing sourdough bread and $B$ be the event of choosing without - cheese.
$P(A) = 65\%$, $P(B)=15\% + 10\%=25\%$, $P(A\cap B)=10\%$.

Step2: Substitute values into formula

$P(A\cup B)=65\%+25\% - 10\%$
$P(A\cup B)=80\%$

Answer:

$80\%$