Question

1. for a water tank draining at a constant rate, if the tank holds 200 gallons and drains at 10 gallons per hour, the linear equation representing the remaining water (w) after t hours is:

a. $w = 200 - 10t$
b. $w = 200 + 10t$
c. $w = 10t - 200$
d. $w = 200 \times 10t$

Explanation:

Step1: Identify initial water

Initial water \( w_0 = 200 \) gallons

Step2: Calculate drained water

Drained water = rate × time = \( 10t \) gallons

Step3: Form remaining water equation

Remaining water \( w = 200 - 10t \)

Answer:

a. \( w = 200 - 10t \)