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we have calculated $(x - \\bar{x})^2$ for each data value in the data s…

Question

we have calculated $(x - \bar{x})^2$ for each data value in the data set.

x12579
$x - \bar{x}$-3.8-2.80.22.24.2
$(x - \bar{x})^2$14.447.840.044.8417.64

now use the defining formula for sample standard deviation $s = \sqrt{\frac{\sum(x - \bar{x})^2}{n - 1}}$ with $n = 5$. recall that the sum is taken over all.
$s = \sqrt{\frac{\sum(x - \bar{x})^2}{n - 1}}$
$=\sqrt{\frac{14.44 + 7.84 + 0.04+\square+ 17.64}{5 - 1}}$
$=\sqrt{\frac{\square}{4}}$
$=\square$

Explanation:

Step1: Identify sum of squared - deviations

We know the values of \((x - \bar{x})^2\) are \(14.44\), \(7.84\), \(0.04\), \(4.84\), \(17.64\). The sum \(\sum(x - \bar{x})^2=14.44 + 7.84+0.04 + 4.84+17.64\).

Step2: Calculate sum

\(\sum(x - \bar{x})^2=14.44+7.84 + 0.04+4.84+17.64 = 44.8\).

Step3: Apply sample - standard deviation formula

The formula for sample standard deviation is \(s=\sqrt{\frac{\sum(x - \bar{x})^2}{n - 1}}\), with \(n = 5\). Substitute \(\sum(x - \bar{x})^2 = 44.8\) and \(n=5\) into the formula: \(s=\sqrt{\frac{44.8}{5 - 1}}=\sqrt{\frac{44.8}{4}}\).

Step4: Calculate standard deviation

\(\sqrt{\frac{44.8}{4}}=\sqrt{11.2}\approx3.35\).

Answer:

\(3.35\)