Question

1. what is the acceleration of a car moving along a straight road that increases its speed from 0 to 88 miles per hour in 10 seconds?

Explanation:

Step1: Convert speed to SI - units

First, convert 88 miles per hour to meters per second. 1 mile = 1609.34 meters and 1 hour = 3600 seconds. So, $v = 88\times\frac{1609.34}{3600}\text{ m/s}\approx39.3\text{ m/s}$. The initial velocity $u = 0\text{ m/s}$.

Step2: Use acceleration formula

The formula for acceleration is $a=\frac{v - u}{t}$. Here, $v$ is the final velocity, $u$ is the initial velocity, and $t$ is the time. Substitute $u = 0\text{ m/s}$, $v\approx39.3\text{ m/s}$, and $t = 10\text{ s}$ into the formula. $a=\frac{39.3 - 0}{10}\text{ m/s}^2=3.93\text{ m/s}^2$.

Answer:

$3.93\text{ m/s}^2$