Question

what are all the solutions of $x^2 + 3x - 4 = 0$?$square$ $-4LXB0square$ $-1LXB1square$ $1LXB2square$ $4$done

Explanation:

Step1: Factor the quadratic equation

$x^2 + 3x - 4 = (x + 4)(x - 1) = 0$

Step2: Solve for x

Set each factor equal to 0:
$x + 4 = 0 \implies x = -4$
$x - 1 = 0 \implies x = 1$

Answer:

-4, 1