Question

what is the area of the figure? figure with dimensions: 7 in, 6 in, 8 in, 4 in, 16 in options: 80 square inches, 112 square inches, 120 square inches, 80 square inches (note: likely typo in options but extracted as is)

Explanation:

Step1: Find area of outer rectangle

The outer rectangle has length $16$ m and height $7$ m. Area of a rectangle is $\text{length} \times \text{height}$.
$\text{Area}_{\text{rectangle}} = 16 \times 7 = 112$ $\text{m}^2$

Step2: Find area of missing triangle

The missing shape is an isosceles triangle. Its base is $8+8=16$ m, and its height is $7-4=3$ m. Area of a triangle is $\frac{1}{2} \times \text{base} \times \text{height}$.
$\text{Area}_{\text{triangle}} = \frac{1}{2} \times 16 \times 3 = 24$ $\text{m}^2$

Step3: Subtract triangle area from rectangle

The figure's area is the rectangle area minus the missing triangle area.
$\text{Area}_{\text{figure}} = 112 - 24 = 88$ $\text{m}^2$

Answer:

88 square meters