Question

what is the average kinetic energy of the electrons ejected based on the incident light and the work function?
$w_{ag} = 5.6 \times 10^{-19}$ j
$e_{i} = 7.95 \times 10^{-19}$ j
$ke = ? \times 10^{?}$ j

Explanation:

Step1: Recall photoelectric effect formula

The relationship between incident photon energy ($E_I$), work function ($W$), and maximum kinetic energy of ejected electrons ($KE$) is:
$$KE = E_I - W_{Ag}$$

Step2: Substitute given values

$$KE = 7.95 \times 10^{-19}\ \text{J} - 5.6 \times 10^{-19}\ \text{J}$$

Step3: Calculate the difference

$$KE = 2.35 \times 10^{-19}\ \text{J}$$

Answer:

$2.35 \times 10^{-19}$ J