Question

what is the axis of symmetry of $h(x)=5x^{2}+40x+64?LXB0x=-4LXB1x=16$

Explanation:

Step1: Recall axis of symmetry formula

For quadratic $ax^2+bx+c$, axis is $x=-\frac{b}{2a}$

Step2: Identify a and b values

$a=5$, $b=40$

Step3: Substitute into formula

$x=-\frac{40}{2\times5}$

Step4: Calculate the result

$x=-\frac{40}{10}=-4$

Answer:

x = -4