Question

what are the bond angles in the structure shown below? angle 1 = 109.5°, angle 2 = 109.5°, and angle 3 = 109.5° angle 1 = 120°, angle 2 = 120°, and angle 3 = 120° angle 1 = 109.5°, angle 2 = - 109.5°, and angle 3 = 120° angle 1 = 109.5°, angle 2 = 90°, and angle 3 = - 109.5° angle 1 = 109.5°, angle 2 = 120°, and angle 3 = 120°

Explanation:

Step1: Analyze hybridization of atoms

The first - carbon (with 4 single bonds) is $sp^{3}$ hybridized. The bond - angle around an $sp^{3}$ hybridized atom is approximately $109.5^{\circ}$. So, Angle 1 is $109.5^{\circ}$.

Step2: Analyze second atom's hybridization

The sulfur atom has 4 electron - groups (3 single bonds and 1 lone pair), which is $sp^{3}$ hybridized. The bond - angle around it is approximately $109.5^{\circ}$. So, Angle 2 is $109.5^{\circ}$.

Step3: Analyze third atom's hybridization

The last carbon (double - bonded to oxygen and single - bonded to sulfur) is $sp^{2}$ hybridized. The bond - angle around an $sp^{2}$ hybridized atom is $120^{\circ}$. So, Angle 3 is $120^{\circ}$.

Answer:

Angle 1 = $109.5^{\circ}$, Angle 2 = $109.5^{\circ}$, and Angle 3 = $120^{\circ}$