Question

what is the center of the circle given by the equation (x + 5)^2+(y - 8)^2 = 1?
a. (5, -8)
b. (-5, 8)
c. (-5, -8)
d. (5, 8)

Explanation:

Step1: Recall circle - equation formula

The standard form of the equation of a circle is $(x - h)^2+(y - k)^2=r^2$, where $(h,k)$ is the center of the circle and $r$ is the radius.

Step2: Rewrite the given equation

The given equation is $(x + 5)^2+(y - 8)^2 = 1$, which can be rewritten as $(x-(-5))^2+(y - 8)^2=1^2$.

Answer:

B. (-5, 8)