Question

what is the change in velocity of a 1323 kg truck that experiences an impulse of 301 n·s? include 2 decimal places in your answer. δv=

Explanation:

Step1: Recall impulse - momentum theorem

The impulse - momentum theorem states that impulse $J$ is equal to the change in momentum $\Delta p$, and $\Delta p = m\Delta v$, where $m$ is mass and $\Delta v$ is the change in velocity. So $J=m\Delta v$.

Step2: Solve for $\Delta v$

We can re - arrange the formula $J = m\Delta v$ to get $\Delta v=\frac{J}{m}$. Given $J = 301\ N\cdot s$ and $m = 1323\ kg$, then $\Delta v=\frac{301}{1323}$.

Step3: Calculate the value

$\Delta v=\frac{301}{1323}\approx0.23\ m/s$

Answer:

$0.23$