Question

what is the formula equation for the reaction between sulfuric acid and dissolved sodium hydroxide if all products and reactants are in the aqueous or liquid phase?
hcl(aq) + naoh(aq) → nacl(s) + h2o(l)
h2so4(aq) + ca(oh)2(aq) → caso4(aq) + 2h2o(l)
h2so4(aq) + 2naoh(aq) → na2so4(aq) + 2h2o(l)
2h3po4(aq) + 3ca(oh)2(aq) → ca3(po4)(s) + 6h2o(l)

Explanation:

Step1: Identify reactants

Sulfuric acid is $H_2SO_4$, sodium - hydroxide is $NaOH$.

Step2: Determine reaction type

It's an acid - base neutralization reaction.

Step3: Predict products

Acid + base gives salt + water. $H_2SO_4$ and $NaOH$ react to form $Na_2SO_4$ and $H_2O$.

Step4: Balance the equation

2 moles of $NaOH$ react with 1 mole of $H_2SO_4$ to balance hydrogen, sodium and sulfate ions.

Answer:

C. $H_2SO_4(aq)+2NaOH(aq)
ightarrow Na_2SO_4(aq)+2H_2O(l)$