Question

what is the greatest 2 - digit integer that is divisible by 9 and a multiple of 5? a. 45 b. 65 c. 90 d. 99 which answer choice is correct? enter a whole number for your answer.

Explanation:

Step1: Recall divisibility rules

A number divisible by 5 ends with 0 or 5. A number divisible by 9 has a sum of digits divisible by 9.

Step2: Analyze each option

• Option A: 45. Sum of digits \(4 + 5 = 9\) (divisible by 9), ends with 5 (multiple of 5). But check other options for greater 2 - digit number.
• Option B: 65. Sum of digits \(6+5 = 11\) (not divisible by 9), so not divisible by 9.
• Option C: 90. Sum of digits \(9 + 0=9\) (divisible by 9), ends with 0 (multiple of 5).
• Option D: 99. Ends with 9, not a multiple of 5.

Step3: Compare valid options

Among 45 and 90, 90 is the greater 2 - digit number.

Answer:

90