Question

what is the heat of reaction (q_rxn), in joules, when q_cal = 49,936.64 j?
q_rxn = ? j
enter either a + or - sign and the magnitude.

Explanation:

Step1: Recall the relationship between \( q_{\text{rxn}} \) and \( q_{\text{cal}} \)

The heat gained by the calorimeter (\( q_{\text{cal}} \)) is equal in magnitude but opposite in sign to the heat of the reaction (\( q_{\text{rxn}} \)). So, \( q_{\text{rxn}} = -q_{\text{cal}} \).

Step2: Substitute the given value of \( q_{\text{cal}} \)

Given \( q_{\text{cal}} = 49936.64 \, \text{J} \), then \( q_{\text{rxn}} = - 49936.64 \, \text{J} \).

Answer:

\(-49936.64\)