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Question
what is the height, x, of the equilateral triangle? triangle with 60° angles, base 14 in., height x options: a. $7\sqrt{3}$ inches, b. 7 inches, c. $14\sqrt{3}$ inches, d. 14 inches, e. $7\sqrt{2}$ inches
Step1: Identify side length
All sides of equilateral triangle are equal, so side length \(s = 14\) inches.
Step2: Split into right triangles
Height splits base into two equal parts: \(\frac{s}{2} = 7\) inches.
Step3: Apply Pythagorean theorem
Height \(x = \sqrt{s^2 - (\frac{s}{2})^2} = \sqrt{14^2 - 7^2}\)
Step4: Calculate value
\(x = \sqrt{196 - 49} = \sqrt{147} = 7\sqrt{3}\) inches.
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A. \(7\sqrt{3}\) inches