Question

what is the y - intercept of the function?
$f(x)= - 0.2x^{2}+0.3x - 0.8$
the y - intercept is \\(\square\\). (type an ordered pair, using integers or decimals.)

Explanation:

Step1: Recall y-intercept definition

The y - intercept of a function \( f(x) \) is the point where \( x = 0 \). So we substitute \( x = 0 \) into the function \( f(x)=- 0.2x^{2}+0.3x - 0.8 \).

Step2: Substitute x = 0

When \( x = 0 \), we have \( f(0)=-0.2(0)^{2}+0.3(0)-0.8 \).
Simplify each term: \( - 0.2(0)^{2}=0 \), \( 0.3(0) = 0 \). So \( f(0)=-0.8 \).
The ordered pair for the y - intercept is \( (0,-0.8) \) since when \( x = 0 \), \( y=f(0)=-0.8 \).

Answer:

\((0, - 0.8)\)