Question

what line of reflection will give an image with point e at (-4,-1)? y=x y=1 x=0 y=-x

Explanation:

Step1: Recall reflection rules

The rule for reflecting a point $(x,y)$ over the line $y = -x$ is $(x,y)\to(-y,-x)$.

Step2: Assume initial point of E

Suppose the initial point of E is $(1,4)$. When we reflect the point $(1,4)$ over the line $y=-x$, using the rule $(x,y)\to(-y,-x)$, we get $(-4,-1)$.

Answer:

D. $y = -x$