Question

what mass of bacl₂ is required to generate 12.0 g baso₄? molar mass baso₄ = 233.39 g/mol molar mass bacl₂ = 208.23 g/mol bacl₂ + na₂so₄ → baso₄(s) + 2nacl ? g bacl₂

Explanation:

Step1: Calculate moles of BaSO₄

Moles = $\frac{mass}{molar\ mass}$. For BaSO₄, mass = 12.0 g, molar mass = 233.39 g/mol. So moles of BaSO₄ = $\frac{12.0\ g}{233.39\ g/mol}$.

Step2: Determine moles of BaCl₂

From the balanced equation, 1 mole of BaCl₂ produces 1 mole of BaSO₄. So moles of BaCl₂ = moles of BaSO₄.

Step3: Calculate mass of BaCl₂

Mass = moles × molar mass. Molar mass of BaCl₂ is 208.23 g/mol. So mass = ($\frac{12.0\ g}{233.39\ g/mol}$) × 208.23 g/mol.
First, calculate $\frac{12.0}{233.39} \approx 0.05142$ mol (moles of BaSO₄ and BaCl₂). Then, mass = 0.05142 mol × 208.23 g/mol ≈ 10.71 g.

Answer:

10.7 g (or more precisely 10.71 g)