Question

what mass of bacl₂ is required to generate 12.0 g baso₄? molar mass baso₄ = 233.39 g/mol molar mass bacl₂ = 208.23 g/mol bacl₂ + na₂so₄ → baso₄(s) + 2nacl ? g bacl₂

Explanation:

Step1: Calculate moles of \( BaSO_4 \)

Moles of \( BaSO_4 = \frac{\text{mass of } BaSO_4}{\text{molar mass of } BaSO_4} \)
\( \text{Moles of } BaSO_4 = \frac{12.0\ g}{233.39\ g/mol} \approx 0.05142\ mol \)

Step2: Determine moles of \( BaCl_2 \)

From the balanced equation, the mole ratio of \( BaCl_2 \) to \( BaSO_4 \) is \( 1:1 \). So, moles of \( BaCl_2 \) = moles of \( BaSO_4 \) = \( 0.05142\ mol \)

Step3: Calculate mass of \( BaCl_2 \)

Mass of \( BaCl_2 = \text{moles} \times \text{molar mass} \)
\( \text{Mass of } BaCl_2 = 0.05142\ mol \times 208.23\ g/mol \approx 10.71\ g \)

Answer:

\( 10.7\ g \) (or more precisely \( 10.71\ g \))