Question

what mass of na₂so₄ is required to generate 12.0 g baso₄? molar mass baso₄ = 233.39 g/mol molar mass na₂so₄ = 142.04 g/mol bacl₂ + na₂so₄ → baso₄(s) + 2nacl ? g na₂so₄

Explanation:

Step1: Calculate moles of \( BaSO_4 \)

Moles of \( BaSO_4 = \frac{\text{mass of } BaSO_4}{\text{molar mass of } BaSO_4} = \frac{12.0\ g}{233.39\ g/mol} \)

Step2: Determine moles of \( Na_2SO_4 \)

From the balanced equation, the mole ratio of \( Na_2SO_4 \) to \( BaSO_4 \) is \( 1:1 \), so moles of \( Na_2SO_4 \) = moles of \( BaSO_4 \)

Step3: Calculate mass of \( Na_2SO_4 \)

Mass of \( Na_2SO_4 = \text{moles of } Na_2SO_4 \times \text{molar mass of } Na_2SO_4 = \frac{12.0\ g}{233.39\ g/mol} \times 142.04\ g/mol \)

Answer:

\( \frac{12.0 \times 142.04}{233.39} \approx 7.23 \) g (rounded to three significant figures)