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if $r = \\begin{bmatrix}-9 & 6\\\\ -5 & 0\\\\ 6 & 7\\end{bmatrix}$ and …

Question

if $r = \

$$\begin{bmatrix}-9 & 6\\\\ -5 & 0\\\\ 6 & 7\\end{bmatrix}$$

$ and $z = 9$, what is $zr$?\
if the matrix exists, select its size before entering your answer. if the matrix does not exist, select undefined.\
$zr = \

$$\begin{bmatrix}\\square\\end{bmatrix}$$

$\
matrix size options: 1×1, 1×2, 1×3, 1×4, 2×1, 2×2, 2×3, 2×4, 3×1, 3×2, 3×3, 3×4, 4×1, 4×2, 4×3, 4×4, undefined

Explanation:

Step1: Multiply scalar by each entry

Multiply $z=9$ by every element in $R$.

Step2: Calculate first row entries

$9\times(-9) = -81$, $9\times6 = 54$

Step3: Calculate second row entries

$9\times(-5) = -45$, $9\times0 = 0$

Step4: Calculate third row entries

$9\times6 = 54$, $9\times7 = 63$

Step5: Construct resulting matrix

$$zR = LATEXBLOCK0 $$

Answer:

$zR =

$$\begin{bmatrix} -81 & 54 \\ -45 & 0 \\ 54 & 63 \end{bmatrix}$$

$
Size: 3×2