Question

what is $(a^2 - 11) + (3a^2 - 4a + 6)$? (1 point)

Explanation:

Step1: Remove parentheses

To add the two polynomials, we first remove the parentheses. Since there are no negative signs outside the parentheses to distribute, we can directly write the terms as they are: \(a^2 - 11 + 3a^2 - 4a + 6\)

Step2: Combine like terms

• For the \(a^2\) terms: \(a^2 + 3a^2 = (1 + 3)a^2 = 4a^2\)
• The \(a\) term remains as \(-4a\) (since there are no other \(a\) terms to combine with)
• For the constant terms: \(-11 + 6 = -5\)

Putting it all together, we get \(4a^2 - 4a - 5\)

Answer:

\(4a^2 - 4a - 5\)