Question

what is the product?
$6\left(x^{2}-1\
ight) \frac{6x - 1}{6\left(x + 1\
ight)}$
$\bigcirc\\ 6\left(x - 1\
ight)^{2}$
$\bigcirc\\ 6\left(x^{2}-1\
ight)$
$\bigcirc\\ \left(x + 1\
ight)\left(6x - 1\
ight)$
$\bigcirc\\ \left(x - 1\
ight)\left(6x - 1\
ight)$

Explanation:

Step1: Factor the difference of squares

$x^2 - 1 = (x+1)(x-1)$

Step2: Substitute and simplify terms

$6(x+1)(x-1) \cdot \frac{6x-1}{6(x+1)} = \frac{6(x+1)(x-1)(6x-1)}{6(x+1)}$
Cancel $6$ and $(x+1)$ from numerator and denominator:
$(x-1)(6x-1)$

Answer:

$(x-1)(6x-1)$