Question

what is the quantity of fe2+ ion reacting, in moles? 100 ml of a 0.500 m solution of fe2+ is added to 100 ml of a 0.100 m solution of mno4-

Explanation:

Step1: Recall the molar - quantity formula

The formula for the number of moles ($n$) is $n = M\times V$, where $M$ is the molarity and $V$ is the volume in liters.

Step2: Convert volumes to liters

The volume of $Fe^{2 + }$ solution $V_{Fe^{2+}}=100\ mL = 0.100\ L$, and its molarity $M_{Fe^{2+}} = 0.500\ M$. The volume of $MnO_4^-$ solution $V_{MnO_4^-}=100\ mL=0.100\ L$, and its molarity $M_{MnO_4^-}=0.100\ M$.

Step3: Calculate the moles of $Fe^{2 + }$

Using the formula $n = M\times V$, for $Fe^{2 + }$, $n_{Fe^{2+}}=M_{Fe^{2+}}\times V_{Fe^{2+}}=0.500\ mol/L\times0.100\ L = 0.0500\ mol$.

Answer:

$0.0500$