Question

what is the solution to $-2(8x - 4) < 2x + 5?LXB0x < \frac{1}{6}LXB1x < 6$

Explanation:

Step1: Expand left-hand side

$-2(8x - 4) = -16x + 8$
Inequality becomes: $-16x + 8 < 2x + 5$

Step2: Move x terms to left

Subtract $2x$ from both sides:
$-16x - 2x + 8 < 5$
$-18x + 8 < 5$

Step3: Move constants to right

Subtract 8 from both sides:
$-18x < 5 - 8$
$-18x < -3$

Step4: Divide by -18, flip inequality

$\frac{-18x}{-18} > \frac{-3}{-18}$
$x > \frac{1}{6}$

Answer:

A. $x > \frac{1}{6}$