Question

what is the solution to the equation below? (x^{2}-36 = 0) a (x=-9,4) b (x = 12,-3) c (x=6,-6) d (x = 36,-1)

Explanation:

Step1: Isolate the variable term

Add 36 to both sides of the equation $x^{2}-36 = 0$, we get $x^{2}=36$.

Step2: Solve for x

Take the square - root of both sides. Remember that if $x^{2}=a$ ($a\geq0$), then $x=\pm\sqrt{a}$. So $x = \pm\sqrt{36}$, which gives $x = 6$ or $x=-6$.

Answer:

C. $x = 6,-6$