Question

what is the solution to this system of linear equations?
7x - 2y = -6
8x + y = 3
○ (-6, 3)
○ (0, 3)
○ (1, -5)
○ (15, -1)

Explanation:

Step1: Solve the second equation for y

From \(8x + y = 3\), we can express \(y\) as \(y = 3 - 8x\).

Step2: Substitute y into the first equation

Substitute \(y = 3 - 8x\) into \(7x - 2y = -6\):
\[

$$\begin{align*} 7x - 2(3 - 8x) &= -6\\ 7x - 6 + 16x &= -6\\ 23x - 6 &= -6\\ 23x &= 0\\ x &= 0 \end{align*}$$

\]

Step3: Find y when x = 0

Substitute \(x = 0\) into \(y = 3 - 8x\):
\(y = 3 - 8(0) = 3\)

Answer:

(0, 3)