Question

what are the solutions to the quadratic equation ( x^2 - 16 = 0 )?
( x = 8 ) and ( x = -8 )
( x = 2 ) and ( x = -2 )
( x = 4 ) and ( x = -4 )
( x = 16 ) and ( x = -16 )

Explanation:

Step1: Isolate the squared term

$x^2 - 16 = 0 \implies x^2 = 16$

Step2: Apply square root property

$x = \pm\sqrt{16}$

Step3: Calculate square root

$x = \pm 4$

Answer:

$x = 4$ and $x = -4$