Question

what is the sum of the squares of the legs of a right triangle with sides a = 5 and b = 12? a. 169 b. 144 c. 17 d. 13 what happens if a² + b² < c² for the sides of a triangle? a. the triangle is acute b. the triangle is equilateral c. the triangle is isosceles d. the triangle is obtuse

Explanation:

Step1: Find square of side a

Calculate $a^{2}$, where $a = 5$. So $a^{2}=5^{2}=25$.

Step2: Find square of side b

Calculate $b^{2}$, where $b = 12$. So $b^{2}=12^{2}=144$.

Step3: Calculate sum of squares

Add $a^{2}$ and $b^{2}$: $a^{2}+b^{2}=25 + 144=169$.

For the second - part:
The Pythagorean - related rule states that if $a^{2}+b^{2}

Answer:

a. 169
d. The triangle is obtuse