Question

what will be the total number of oxygen atoms on either side of the chemical equation shown, once it is balanced? cuso₄ + kno₃ ⟶ k₂so₄ + cu(no₃)₂ ○ 7 ○ 3 ○ 10 ○ 6 which list of coefficients will balance the chemical equation shown? cuso₄ + kno₃ ⟶ k₂so₄ + cu(no₃)₂ ○ 1,2,1,1 ○ 1,1,1,1 ○ 2,2,2,2 ○ 2,1,1,1

Explanation:

Step1: Balance K atoms

Unbalanced: $\text{CuSO}_4 + \text{KNO}_3
ightarrow \text{K}_2\text{SO}_4 + \text{Cu(NO}_3\text{)}_2$
Add coefficient 2 to $\text{KNO}_3$: $\text{CuSO}_4 + 2\text{KNO}_3
ightarrow \text{K}_2\text{SO}_4 + \text{Cu(NO}_3\text{)}_2$

Step2: Verify all atom counts

Cu: 1 on left, 1 on right
S: 1 on left, 1 on right
O: $4 + (2\times3) = 10$ on left; $4 + (2\times3) = 10$ on right
K: 2 on left, 2 on right
N: 2 on left, 2 on right

Step3: Answer first question

Count total O atoms per side.

Step4: Answer second question

Identify the balanced coefficients.

Answer:

1. 10
2. 1, 2, 1, 1