Question

1. what volume would 23.82 grams of mercury occupy? $\frac{23.82}{v}=13.6$ answer:

Explanation:

Step1: Recall density formula

Density $
ho=\frac{m}{V}$, where $m = 23.82$ g and $
ho = 13.6$ g/cm³ for mercury.

Step2: Solve for volume

$V=\frac{m}{
ho}=\frac{23.82}{13.6}$ cm³.
$V = 1.75$ cm³

Answer:

$1.75$ cm³