Question

what volume, in l, of a 0.575 m cu₂so₄ solution contains 0.127 lb of cu₂so₄?

Explanation:

Step1: Convert lb to grams

1 lb = 453.592 g, so $0.127 \text{ lb} \times 453.592 \frac{\text{g}}{\text{lb}} = 57.606 \text{ g}$

Step2: Calculate molar mass of $\text{Cu}_2\text{SO}_4$

Molar mass: $2\times63.55 + 32.07 + 4\times16.00 = 223.17 \frac{\text{g}}{\text{mol}}$

Step3: Find moles of $\text{Cu}_2\text{SO}_4$

Moles $n = \frac{\text{mass}}{\text{molar mass}} = \frac{57.606 \text{ g}}{223.17 \frac{\text{g}}{\text{mol}}} = 0.2581 \text{ mol}$

Step4: Calculate volume using molarity

Molarity $M = \frac{n}{V}$, so $V = \frac{n}{M} = \frac{0.2581 \text{ mol}}{0.575 \frac{\text{mol}}{\text{L}}} = 0.449 \text{ L}$

Answer:

0.449 L