Question

what is the volume of a cylinder with a height of 16.5 m and a base with a radius of 8.9 m, to the nearest tenth of a cubic meter?

Explanation:

Step1: Recall volume formula

The volume formula for a cylinder is $V=\pi r^{2}h$, where $r$ is the radius and $h$ is the height.

Step2: Substitute given values

Given $r = 8.9$ m and $h=16.5$ m. Substitute into the formula: $V=\pi\times(8.9)^{2}\times16.5$.

Step3: Calculate

First, $(8.9)^{2}=79.21$. Then $V=\pi\times79.21\times16.5$. $V=\pi\times1307.965$. Using $\pi\approx3.14$, we get $V\approx3.14\times1307.965 = 4107.0101\approx4107.0$ (rounded to the nearest tenth).

Answer:

$4107.0$