Question

what is the y-value in the solution to this system of linear equations?
$4x + 5y = -12$
$-2x + 3y = -16$
$\circ$ $-4$
$\circ$ $-2$
$\circ$ $2$
$\circ$ $5$

Explanation:

Step1: Eliminate x by multiplying the second equation

Multiply the second equation \(-2x + 3y = -16\) by 2 to get \( -4x + 6y = -32 \).

Step2: Add the two equations

Add the first equation \(4x + 5y = -12\) and the new second equation \( -4x + 6y = -32 \).
\((4x - 4x) + (5y + 6y) = -12 + (-32)\)
\(11y = -44\)

Step3: Solve for y

Divide both sides by 11: \(y = \frac{-44}{11} = -4\).

Answer:

\(-4\)