Question

a. a wheelchair ramp with a length of 100 inches has a horizontal distance of 96 inches. what is the ramp’s vertical distance?
b. construction laws are very specific when it comes to access ramps for the disabled. every vertical rise of 1 inch requires a horizontal run of 12 inches. does this ramp satisfy the requirements?
a. the vertical distance of the ramp is dropdown with square inches, inches

Explanation:

Step1: Apply Pythagorean theorem

Let vertical distance = $x$. The theorem states $a^2 + b^2 = c^2$, so:
$$x^2 + 96^2 = 100^2$$

Step2: Calculate squared values

$$x^2 + 9216 = 10000$$

Step3: Isolate $x^2$

$$x^2 = 10000 - 9216 = 784$$

Step4: Solve for $x$

$$x = \sqrt{784} = 28$$

Step5: Check ramp requirement

For 28-inch rise, required horizontal run is $28 \times 12 = 336$ inches. Compare to actual 96 inches.

Answer:

a. The vertical distance of the ramp is 28 inches
b. No, this ramp does not satisfy the requirements. The required horizontal run for a 28-inch rise is 336 inches, but the ramp only has a 96-inch horizontal run.