Question

when 1.00 g of solid k dissociates in 500.0 g of water in a coffee cup calorimeter, the temperature rises from 21.3 °c to 23.5 °c.
$c_{sol} = 4.18 j/g °c$
$mass_{sol} = 501.0 g$ $q_{sol} = +4,610 j$
what is the heat of reaction, $q_{rxn}$?
$q_{rxn} = ? j$
because the heat capacity of the calorimeter cannot be determined, $q_{rxn} = -q_{sol}$.
enter either a + or - sign and the magnitude.

Explanation:

Step1: Recall the relationship between \( q_{rxn} \) and \( q_{sol} \)

Given that \( q_{rxn} = -q_{sol} \), and we know \( q_{sol} = +4610 \, \text{J} \).

Step2: Calculate \( q_{rxn} \)

Substitute the value of \( q_{sol} \) into the formula: \( q_{rxn} = - 4610 \, \text{J} \)

Answer:

\(-4610\)