Question

1. when baking soda (sodium bicarbonate, nahco₃) reacts with vinegar (acetic acid, ch₃cooh), they undergo a chemical reaction that produces carbon dioxide gas (co₂), water (h₂o), and sodium acetate (ch₃coona). the chemical equation for the reaction is shown below: nahco₃ + ch₃cooh → co₂ + h₂o + ch₃coona. the masses of some reactants and products (in grams) are given: nahco₃ = 84 g, co₂ = 44 g, h₂o = 18 g, ch₃coona = 82 g, ch₃cooh = ? how many grams of acetic acid (ch₃cooh) were used? options (implied: 60 g, 144 g, 100 g, 82 g, etc.)

Explanation:

Step1: Recall the Law of Conservation of Mass

The total mass of reactants equals the total mass of products. The reaction is \( \text{NaHCO}_3 + \text{CH}_3\text{COOH}
ightarrow \text{CO}_2 + \text{H}_2\text{O} + \text{CH}_3\text{COONa} \). Let the mass of \( \text{CH}_3\text{COOH} \) be \( x \).

Step2: Identify masses of reactants and products

Reactants: \( \text{NaHCO}_3 = 84 \, \text{g} \), \( \text{CH}_3\text{COOH} = x \)
Products: \( \text{CO}_2 = 44 \, \text{g} \), \( \text{H}_2\text{O} = 18 \, \text{g} \), \( \text{CH}_3\text{COONa} = 82 \, \text{g} \)

Step3: Apply Conservation of Mass

Total mass of reactants = Total mass of products
\( 84 + x = 44 + 18 + 82 \)

Step4: Calculate the right-hand side

\( 44 + 18 + 82 = 144 \)

Step5: Solve for \( x \)

\( x = 144 - 84 = 60 \)

Answer:

60 g