Question

1. which equation is correct for the circle shown on the graph below? (x - 3)^2+(y - 0)^2 = 1 (x + 3)^2+(y - 0)^2 = 1

Explanation:

Step1: Recall circle - equation formula

The standard form of the equation of a circle is \((x - h)^2+(y - k)^2=r^2\), where \((h,k)\) is the center of the circle and \(r\) is the radius.

Step2: Identify the center and radius from the graph

From the graph, the center of the circle is \((3,0)\) and the radius \(r = 1\).

Step3: Substitute values into the formula

Substitute \(h = 3\), \(k = 0\), and \(r = 1\) into \((x - h)^2+(y - k)^2=r^2\). We get \((x - 3)^2+(y - 0)^2=1\).

Answer:

\((x - 3)^2+(y - 0)^2=1\)