Question

which equation is correct and can be used to solve for the value of z? law of sines: $\frac{sin(a)}{a}=\frac{sin(b)}{b}=\frac{sin(c)}{c}$ $\frac{sin(51^{circ})}{2.6}=\frac{sin(76^{circ})}{z}$ $\frac{sin(51^{circ})}{2.6}=\frac{sin(53^{circ})}{z}$ $\frac{sin(76^{circ})}{2.6}=\frac{sin(51^{circ})}{z}$ $\frac{sin(76^{circ})}{2.6}=\frac{sin(53^{circ})}{z}$

Explanation:

Step1: Calculate angle at X

Sum of angles in triangle: 180° - 51° - 76° = 53°

Step2: Apply Law of Sines

Angle Y=51° (opposite side 2.6), angle X=53° (opposite side z). Thus, sin(51°)/2.6 = sin(53°)/z

Answer:

B. sin(51°)/2.6 = sin(53°)/z