Question

which equation has infinitely many solutions? a -8x + 3 = 8x b 0 = 8x - 8x c 8x - 3x = 15 d 8x = 1 + 8x

Explanation:

Step1: Simplify option A

-8x + 3 = 8x can be rewritten as 3=16x, which has one - solution $x=\frac{3}{16}$.

Step2: Simplify option B

0 = 8x - 8x simplifies to 0 = 0. This is an identity, meaning it is true for all real - values of x, so it has infinitely many solutions.

Step3: Simplify option C

8x - 3x = 15 simplifies to 5x = 15, and then $x = 3$, which has one solution.

Step4: Simplify option D

8x = 1+8x can be rewritten as 0 = 1, which is a contradiction and has no solutions.

Answer:

B. 0 = 8x - 8x