Question

which expressions can be used to find m∠bac? select three options. cos⁻¹(6.9/12) cos⁻¹(9.8/12) sin⁻¹(6.9/12) sin⁻¹(9.8/12) tan⁻¹(9.8/6.9)

Explanation:

Step1: Identify right triangle sides for ∠BAC

Right angle at C; hypotenuse AB=12cm, adj AC=6.9cm, opp BC=9.8cm.

Step2: Apply trigonometric ratios for ∠BAC

cos(∠BAC)=adj/hyp=6.9/12 ⇒ ∠BAC=cos⁻¹(6.9/12); sin(∠BAC)=opp/hyp=9.8/12 ⇒ ∠BAC=sin⁻¹(9.8/12); tan(∠BAC)=opp/adj=9.8/6.9 ⇒ ∠BAC=tan⁻¹(9.8/6.9).

Answer:

A. cos⁻¹(6.9/12), D. sin⁻¹(9.8/12), E. tan⁻¹(9.8/6.9)