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Question
which model shows that it was sunny \\(\frac{2}{3}\\) of the days in june?
Step1: Determine total days in June
June has 30 days. So total days \( n = 30 \).
Step2: Calculate number of sunny days for \(\frac{2}{3}\) of 30
We need to find \(\frac{2}{3}\) of 30. The formula for finding a fraction of a number is \( \text{Number of sunny days} = \frac{2}{3} \times 30 \).
Calculating this: \( \frac{2}{3} \times 30 = 2\times10 = 20 \). So we need to find the model with 20 sunny days.
Step3: Count sunny days in each model
- First model: Let's count the suns. After counting, we find it's less than 20.
- Second model: Counting the suns, we get 3 (from 5 - 7) + 3 (from 21 - 23) = 6? Wait, no, let's recount. Wait, first model: Let's list the days with sun: 2,5,9,10,11,14,20,22,26,28. Wait, no, maybe better to count each model:
Wait, third model: Let's count. Days with sun: 2,3,5,6,7,8,10,11,13,14,15,16,19,20,21,22,23,25,28,29. Wait, that's 20? Wait, let's do properly:
First model: Let's count the sun icons:
Day 2: 1
Day 5:1
Day9:1
Day10:1
Day11:1
Day14:1
Day20:1
Day22:1
Day26:1
Day28:1. Wait, that's 10? No, maybe I miscounted. Wait, the second model:
Days 5,6,7: 3
Days 21,22,23:3. Total 6? No, that can't be. Wait, third model:
Let's count all suns:
Row 1 (days 1 - 3): 2 (days 2,3)
Row 2 (days 4 - 10): days 5,6,7,8,10: 5 (wait, day 4: no, day5: sun, day6: sun, day7: sun, day8: sun, day10: sun. So 5)
Row 3 (days 11 - 17): days 11,13,14,15,16: 5 (day11: sun, day13: sun, day14: sun, day15: sun, day16: sun)
Row 4 (days 18 - 24): days 19,20,21,22,23: 5 (day19: sun, day20: sun, day21: sun, day22: sun, day23: sun)
Row 5 (days 25 - 30): days 25,28,29: 3 (day25: sun, day28: sun, day29: sun)
Now sum: 2 + 5 + 5 + 5 + 3 = 20. Yes! So the third model has 20 sunny days, which is \(\frac{2}{3}\) of 30 (since \(\frac{2}{3}\times30 = 20\)).
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The third model (the right - most one) shows that it was sunny \(\frac{2}{3}\) of the days in June.