QUESTION IMAGE
Question
which one of the following is the correct electron configuration for a ground - state nitrogen atom? none of the above is correct. question 22 the ground - state electron configuration of the element ____ is kr5s^14d^5. mn tc mo
Step1: Recall nitrogen's atomic number
Nitrogen has atomic number 7, so it has 7 electrons.
Step2: Apply electron - filling rules
Electrons fill the 1s orbital first (2 electrons), then the 2s orbital (2 electrons), and then the 2p orbital (3 electrons). According to Hund's rule, in the 2p orbital, the 3 electrons will occupy separate orbitals with parallel spins. The correct electron - configuration for nitrogen in box - notation is 1s<sup>2</sup>2s<sup>2</sup>2p<sup>3</sup> which is represented as two electrons in 1s (paired, opposite spins), two electrons in 2s (paired, opposite spins) and three unpaired electrons in 2p (same - spin).
Step3: Analyze the given options
The first option shows 1s<sup>2</sup>2s<sup>2</sup>2p<sup>3</sup> with correct electron - pairing and spin in each orbital.
Step4: Recall electron - configuration for the second question
The electron - configuration [Kr]5s<sup>1</sup>4d<sup>5</sup> corresponds to an element with 36 (Kr) + 1+5 = 42 electrons.
Step5: Identify the element
Molybdenum (Mo) has an atomic number of 42 and its ground - state electron - configuration is [Kr]5s<sup>1</sup>4d<sup>5</sup> due to the stability of half - filled d - subshell.
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Question 1: First option (1s box with two electrons of opposite spins, 2s box with two electrons of opposite spins, 2p boxes with three unpaired electrons of same spin)
Question 2: Mo