QUESTION IMAGE
Question
- which one of the following values satisfies the inequality $42 \leq 6p$? \\(\bigcirc\\) $p = 8$ \\(\bigcirc\\) $p = 6$ \\(\bigcirc\\) $p = 4$ \\(\bigcirc\\) $p = 2$
Step1: Solve the inequality for \( p \)
To solve \( 42 \leq 6p \), we divide both sides by 6.
\[
\frac{42}{6} \leq \frac{6p}{6}
\]
Simplifying, we get \( 7 \leq p \), which means \( p \) must be greater than or equal to 7.
Step2: Check each option
- For \( p = 8 \): \( 8 \geq 7 \), so this satisfies the inequality.
- For \( p = 6 \): \( 6 < 7 \), so this does not satisfy the inequality.
- For \( p = 4 \): \( 4 < 7 \), so this does not satisfy the inequality.
- For \( p = 2 \): \( 2 < 7 \), so this does not satisfy the inequality.
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A. \( p = 8 \)