Question

which ordered pair is a solution to this equation? 2x + 3y = 16 (3, 2) (7, 2) (11, 1) (5, 2)

Explanation:

Step1: Substitute (3, 2) into the equation

Substitute \(x = 3\) and \(y=2\) into \(2x + 3y\). We get \(2\times3+3\times2=6 + 6=12
eq16\).

Step2: Substitute (7, 2) into the equation

Substitute \(x = 7\) and \(y = 2\) into \(2x+3y\). We get \(2\times7+3\times2=14 + 6=20
eq16\).

Step3: Substitute (11, 1) into the equation

Substitute \(x = 11\) and \(y = 1\) into \(2x+3y\). We get \(2\times11+3\times1=22 + 3=25
eq16\).

Step4: Substitute (5, 2) into the equation

Substitute \(x = 5\) and \(y = 2\) into \(2x+3y\). We get \(2\times5+3\times2=10+6 = 16\).

Answer:

D. \((5,2)\)