Question

which statement could be placed in step 2? a any circle that contains s and t has its center on the bisector of (overline{st}), (x = 6). b any circle that contains s and t has its center on the segment that intersects (overline{st}), (x = 3). c any circle that contains s and t has its center on the perpendicular bisector of (overline{st}), (y = 6). d any circle that contains s and t has its center on the segment perpendicular to (overline{st}), (y = 5).

Explanation:

The key geometric principle is that the center of a circle passing through two points lies on the perpendicular bisector of the line - segment joining those two points.

Answer:

C. Any circle that contains S and T has its center on the perpendicular bisector of $\overline{ST}, y = 6$.